χR(∣qubit_sqrtT⟩⊗5) ≤ 6

√T orbit, qubit.

Participate

Run it yourself, or point a coding agent at it.

git clone https://github.com/unitaryfoundation/stabrank
cd stabrank
# describe your decomposition in bounds/mybound.json
make fit BOUND=bounds/mybound.json ARGS=--write
make verify BOUND=bounds/mybound.json

fit solves for the exact coefficients, or tells you no exact combination of your terms reproduces the target. verify rebuilds the identity in exact arithmetic. If it passes, open a pull request adding the file and the leaderboard picks it up on the next build.

A bound the pipeline cannot check is recorded as cited and never takes a record.

← back to the board

Verification

verified   6 stabilizer terms reproduce |qubit_sqrtT>^{ot 5}, checked symbolically

Implied per-copy exponent γ ≤ 0.5170 against a published 0.5000, no improvement.

Compute

1 run; 0.001 CPU-hours; 0.001 h wall-clock; on Apple silicon laptop, one core; direct construction, no search.

Notes

The six product states φ^5 over the single-qubit stabilizer states are independent in the six-dimensional symmetric subspace (in the Hamming-weight basis they are e0, e5, and the Vandermonde rows (z^w)_w for z = 1, -1, i, -i), so they span Sym^5 and every symmetric five-qubit state, |sqrtT⟩⊗5 among them, has χ ≤ 6; this is the generic value chi_5 = 6 of Lovitz and Steffan (arXiv:2110.07781, Section 1.3). With qubit_sqrtT-m5-lower-6.json (exact census through the Galois-forced subspace) the cell is exact, χ(|sqrtT⟩⊗5) = 6, γ log_2(6)/5 = 0.5170 against the published 1/2. The construction stops here: at six qubits the six product states span only the hyperplane f(1) = f(5) of Sym^6, and every symmetric six-qubit stabilizer state has equal amplitudes on weights 1 and 5, so Sym^6 is not spanned by symmetric stabilizer states and a seven-term decomposition of |sqrtT⟩⊗6, which would beat 1/2, needs non-symmetric terms.

Attribution

Vincent Russo · this repository (stabrank-research, round 33) · by hand: the six product stabilizer states |0⟩⊗5, |1⟩⊗5, |+⟩⊗5, |→^5, |+i⟩⊗5, |-i⟩⊗5 span Sym^5(C^2); coefficients solved exactly in Q(zeta_16)

Submission

JSON
{
  "schema_version": "0.1",
  "orbit": "qubit_sqrtT",
  "m": 5,
  "direction": "upper",
  "rank": 6,
  "witness": {
    "terms": [
      {
        "k": 0,
        "x0": [
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        ],
        "W": [],
        "Q": [],
        "l": []
      },
      {
        "k": 0,
        "x0": [
          1,
          1,
          1,
          1,
          1
        ],
        "W": [],
        "Q": [],
        "l": []
      },
      {
        "k": 5,
        "x0": [
          0,
          0,
          0,
          0,
          0
        ],
        "W": [
          [
            1,
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          ],
          [
            0,
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          [
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          [
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          [
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        ],
        "Q": [
          [
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          [
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          ]
        ],
        "l": [
          0,
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          0
        ]
      },
      {
        "k": 5,
        "x0": [
          0,
          0,
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          0,
          0
        ],
        "W": [
          [
            1,
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          [
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          [
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        ],
        "Q": [
          [
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          ],
          [
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          ],
          [
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          ],
          [
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          ],
          [
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          ]
        ],
        "l": [
          2,
          2,
          2,
          2,
          2
        ]
      },
      {
        "k": 5,
        "x0": [
          0,
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          0,
          0
        ],
        "W": [
          [
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          ],
          [
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        ],
        "l": [
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        ]
      },
      {
        "k": 5,
        "x0": [
          0,
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        ],
        "W": [
          [
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        ],
        "l": [
          3,
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        ]
      }
    ],
    "coeffs": [
      "sqrt(2)/8 - sqrt(2)*I/8",
      "-sqrt(2)*exp(I*pi/8)/8 + sqrt(2)*exp(5*I*pi/8)/8",
      "exp(I*pi/8)/4 + exp(I*pi/4)/4 + exp(3*I*pi/8)/4 + I/4",
      "-exp(3*I*pi/8)/4 - exp(I*pi/8)/4 + exp(I*pi/4)/4 + I/4",
      "-exp(5*I*pi/8)/4 - exp(I*pi/4)/4 + exp(7*I*pi/8)/4 + I/4",
      "-exp(I*pi/4)/4 - exp(7*I*pi/8)/4 + exp(5*I*pi/8)/4 + I/4"
    ]
  },
  "provenance": {
    "author": "Vincent Russo",
    "reference": "this repository (stabrank-research, round 33)",
    "method": "by hand: the six product stabilizer states |0>^5, |1>^5, |+>^5, |->^5, |+i>^5, |-i>^5 span Sym^5(C^2); coefficients solved exactly in Q(zeta_16)",
    "date": "2026-10-23",
    "github": [
      "vprusso"
    ],
    "compute": {
      "cpu_hours": 0.001,
      "wall_clock_hours": 0.001,
      "runs": 1,
      "hardware": "Apple silicon laptop, one core; direct construction, no search"
    }
  },
  "notes": "The six product states phi^5 over the single-qubit stabilizer states are independent in the six-dimensional symmetric subspace (in the Hamming-weight basis they are e_0, e_5, and the Vandermonde rows (z^w)_w for z = 1, -1, i, -i), so they span Sym^5 and every symmetric five-qubit state, |sqrtT>^5 among them, has chi <= 6; this is the generic value chi_5 = 6 of Lovitz and Steffan (arXiv:2110.07781, Section 1.3). With qubit_sqrtT-m5-lower-6.json (exact census through the Galois-forced subspace) the cell is exact, chi(|sqrtT>^5) = 6, gamma log_2(6)/5 = 0.5170 against the published 1/2. The construction stops here: at six qubits the six product states span only the hyperplane f(1) = f(5) of Sym^6, and every symmetric six-qubit stabilizer state has equal amplitudes on weights 1 and 5, so Sym^6 is not spanned by symmetric stabilizer states and a seven-term decomposition of |sqrtT>^6, which would beat 1/2, needs non-symmetric terms."
}